Mathematics
The terms "maximum" and "minimum" refer to the largest and smallest values, respectively, within a set of data or a defined range.
Here's a breakdown of their differences:
- Maximum: Represents the highest or greatest value.
- Minimum: Represents the lowest or smallest value.
Key Differences Summarized:
- Direction: Maximum points towards the largest value; minimum points towards the smallest value.
- Extremes: They represent opposite extremes within a given set.
Here's the breakdown of divisibility for the numbers 2 and 4:
-
2:
- The number 2 is a prime number.
- Prime numbers are only divisible by 1 and themselves.
- Therefore, 2 is only divisible by 1 and 2.
-
4:
- The number 4 is not a prime number.
- The factors of 4 are 1, 2, and 4.
- Therefore, 4 is divisible by 1, 2, and 4.
The cost for 31 dictionaries can be calculated by multiplying the cost of one dictionary by the number of dictionaries.
Cost of 31 dictionaries = Cost of one dictionary × 31
Cost of 31 dictionaries = ₹ 162 × 31
Cost of 31 dictionaries = ₹ 5,022
Therefore, ₹ 5,022 must be paid for 31 dictionaries.
While asleep, I had an unusual experience. There was a red screen formed by flowing blood, as it were. I was observing it. Suddenly a hand began to write on the screen. I became all attention. That hand wrote a number of elliptic integrals. They stuck to my mind. As soon as I woke up, I committed them to writing.
Compound interest is the interest calculated on the principal amount and also on the accumulated interest of previous periods. It can be thought of as "interest on interest," making a sum grow at a faster rate than simple interest, which is calculated only on the principal amount.
- A = P (1 + r/n)^(nt)
- A = the future value of the investment/loan, including interest
- P = the principal investment amount (the initial deposit or loan amount)
- r = the annual interest rate (as a decimal)
- n = the number of times that interest is compounded per year
- t = the number of years the money is invested or borrowed for
Suppose you invest $1,000 at an annual interest rate of 5% compounded annually for 10 years.
- P = $1,000
- r = 0.05
- n = 1
- t = 10
A = 1000 (1 + 0.05/1)^(1*10) = 1000 * (1.05)^10 ≈ $1,628.89
After 10 years, your investment would grow to approximately $1,628.89.
- Compounding Frequency: The more frequently interest is compounded (e.g., daily, monthly, quarterly), the faster the investment grows.
- Future Value: Compound interest helps in projecting the future value of an investment.