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Here are the conversions from centimeters (cm) and meters (m) to millimeters (mm):

  1. A) 1 cm: There are 10 mm in 1 cm.
  2. B) 4 cm: There are 40 mm in 4 cm.
  3. C) 0.5 cm: There are 5 mm in 0.5 cm.
  4. D) 6.7 cm: There are 67 mm in 6.7 cm.
  5. E) 1 m: There are 1000 mm in 1 m.

Conversion Factor: 1 cm = 10 mm, 1 m = 1000 mm

Wrote answer · 3/14/2025
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6 upon 5
Wrote answer · 2/17/2023
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In point (-3, 5), x-coordinate is negative and y-coordinate is positive, So, the point lies in the second quadrant.
Wrote answer · 10/24/2022
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The volume of a cube is calculated by cubing the length of one of its sides. In other words, Volume = side * side * side.

Given a cube with sides of 3cm, the volume is:

Volume = 3cm * 3cm * 3cm = 27cm3

Therefore, the volume of the cube is 27 cubic centimeters.

Wrote answer · 3/14/2025
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To determine the quadrant in which an angle of -1560 degrees lies, we first need to find its coterminal angle within the range of 0 to 360 degrees.

We can do this by adding multiples of 360 to -1560 until we get an angle in the desired range:

-1560 + 360 = -1200

-1200 + 360 = -840

-840 + 360 = -480

-480 + 360 = -120

-120 + 360 = 240

So, -1560 degrees is coterminal with 240 degrees.

Now we determine the quadrant:

  • Quadrant I: 0° to 90°
  • Quadrant II: 90° to 180°
  • Quadrant III: 180° to 270°
  • Quadrant IV: 270° to 360°

Since 240° is between 180° and 270°, the angle lies in Quadrant III.

Wrote answer · 3/14/2025
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To find the number of integers between 30 and 50, inclusive, we can subtract the lower bound from the upper bound and add 1.

So, the calculation is:

50 - 30 + 1 = 21

Therefore, there are 21 numbers from 30 to 50, inclusive.

Wrote answer · 3/14/2025
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The integral of f(x) * g(x) dx does not have a general, simple formula like the integral of a sum or a constant multiple. Instead, it is usually solved using a technique called integration by parts.

Integration by parts comes from the product rule for differentiation. The formula is:

∫ u dv = uv - ∫ v du

Where:

  • u = f(x) or g(x) (a function to be differentiated)
  • dv = the remaining part of the integrand, including dx (a function to be integrated)
  • du = derivative of u
  • v = integral of dv

Steps to apply integration by parts:

  1. Choose u and dv from the integrand f(x)g(x) dx. A helpful guideline is the acronym LIATE:
    • Logarithmic functions
    • Inverse trigonometric functions
    • Algebraic functions
    • Trigonometric functions
    • Exponential functions
    Choose u based on what comes first in LIATE. The rest becomes dv.
  2. Calculate du (the derivative of u) and v (the integral of dv).
  3. Apply the integration by parts formula: ∫ u dv = uv - ∫ v du
  4. Evaluate the new integral ∫ v du. If it's simpler than the original, the choice of u and dv was good. If not, you might need to try a different choice for u and dv or apply integration by parts again.

Example:

Evaluate ∫ x cos(x) dx

  1. Let u = x (algebraic) and dv = cos(x) dx (trigonometric).
  2. Then du = dx and v = ∫ cos(x) dx = sin(x).
  3. Apply the formula: ∫ x cos(x) dx = x sin(x) - ∫ sin(x) dx
  4. Evaluate the new integral: ∫ sin(x) dx = -cos(x)
  5. Therefore, ∫ x cos(x) dx = x sin(x) - (-cos(x)) + C = x sin(x) + cos(x) + C, where C is the constant of integration.

In summary, there is no direct general formula for the integral of f(x) * g(x) dx. You typically need to use integration by parts.

Wrote answer · 3/14/2025
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