Physics
Kinematics
If displacement is equal to PT squared plus 40 plus 7, determine the instantaneous velocity and acceleration of the body.
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If displacement is equal to PT squared plus 40 plus 7, determine the instantaneous velocity and acceleration of the body.
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To determine the instantaneous velocity and acceleration of the body, we need to perform the following steps, assuming that 'PT squared' refers to 'P times T squared', where P is a constant and T is time:
- Define the displacement equation:
- Calculate the instantaneous velocity:
- Calculate the instantaneous acceleration:
Given: Displacement, s(t) = PT2 + 40T + 7
Instantaneous velocity, v(t), is the first derivative of displacement with respect to time (T).
v(t) = ds/dt = d(PT2 + 40T + 7)/dt
v(t) = 2PT + 40
Instantaneous acceleration, a(t), is the first derivative of velocity with respect to time (T), or the second derivative of displacement with respect to time.
a(t) = dv/dt = d(2PT + 40)/dt
a(t) = 2P
Therefore:
- Instantaneous Velocity: v(t) = 2PT + 40
- Instantaneous Acceleration: a(t) = 2P