
Trigonometry
To convert degrees to radians, you can use the following formula:
Radians = Degrees × (π / 180)
So, for 40 degrees:
Radians = 40 × (π / 180)
Radians = 2π / 9
Radians ≈ 0.698
Therefore, 40 degrees is approximately 0.698 radians.
For more information, you can use online converters. Here's a link to a Google Search
To determine the quadrant in which an angle of -1560 degrees lies, we first need to find its coterminal angle within the range of 0 to 360 degrees.
We can do this by adding multiples of 360 to -1560 until we get an angle in the desired range:
-1560 + 360 = -1200
-1200 + 360 = -840
-840 + 360 = -480
-480 + 360 = -120
-120 + 360 = 240
So, -1560 degrees is coterminal with 240 degrees.
Now we determine the quadrant:
- Quadrant I: 0° to 90°
- Quadrant II: 90° to 180°
- Quadrant III: 180° to 270°
- Quadrant IV: 270° to 360°
Since 240° is between 180° and 270°, the angle lies in Quadrant III.
Here's how to solve this problem:
-
Solve cos(θ) = sin(θ):
-
This equation is true when θ = 45° + 180° * n, where n is any integer. This is because sine and cosine are equal at 45 degrees, and then repeat this relationship every 180 degrees due to their periodicity and phase difference.
-
-
Incorporate the Given Information
-
We are given that θ is 83 times greater than 90 degrees, meaning θ > 83 * 90°. θ > 7470°.
-
-
Find the Appropriate Angle:
-
We need to find an integer n such that θ = 45° + 180° * n and θ > 7470°.
-
Let's solve for n : 45 + 180*n* > 7470
-
180*n* > 7425
-
n > 41.25
-
The smallest integer n that satisfies this condition is n = 42.
-
Therefore, θ = 45° + 180° * 42 = 45° + 7560° = 7605°.
-
-
Calculate 60 * θ
-
60 * θ = 60 * 7605° = 456300°
-
Here's the solution:
-
Solve cos(θ) = sin(θ): This is true when θ = 45° + 180° * n.
-
θ > 83 * 90 = 7470°
-
Find n such that θ = 45 + 180*n > 7470. The smallest integer is n=42.
-
Therefore, θ = 45° + 180° * 42 = 7605°.
-
60 * θ = 60 * 7605° = 456300°.
So, 60 * θ = 456300°
To find the general solution of the equation cot(x) + tan(x) = 2 csc(x), we can rewrite the equation in terms of sine and cosine.
Recall that cot(x) = cos(x)/sin(x), tan(x) = sin(x)/cos(x), and csc(x) = 1/sin(x). Substituting these into the equation, we get:
cos(x)/sin(x) + sin(x)/cos(x) = 2/sin(x)
Multiplying both sides by sin(x)cos(x) to clear the fractions, we obtain:
cos2(x) + sin2(x) = 2cos(x)
Since cos2(x) + sin2(x) = 1, the equation simplifies to:
1 = 2cos(x)
cos(x) = 1/2
The general solution for cos(x) = 1/2 is given by:
x = 2πn ± π/3, where n is an integer.
We need to check for extraneous solutions. The original equation involves cot(x), tan(x), and csc(x), so we must ensure that sin(x) ≠ 0 and cos(x) ≠ 0.
sin(x) ≠ 0 when x ≠ nπ, where n is an integer.
cos(x) ≠ 0 when x ≠ (2n+1)π/2, where n is an integer.
The solutions x = 2πn ± π/3 do not violate these conditions. Therefore, the general solution is:
x = 2πn + π/3 or x = 2πn - π/3, where n is an integer.