If cos(θ) = sin(θ) and θ is 83 times greater than 90 degrees, what is 60 * θ?
If cos(θ) = sin(θ) and θ is 83 times greater than 90 degrees, what is 60 * θ?
Here's how to solve this problem:
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Solve cos(θ) = sin(θ):
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This equation is true when θ = 45° + 180° * n, where n is any integer. This is because sine and cosine are equal at 45 degrees, and then repeat this relationship every 180 degrees due to their periodicity and phase difference.
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Incorporate the Given Information
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We are given that θ is 83 times greater than 90 degrees, meaning θ > 83 * 90°. θ > 7470°.
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Find the Appropriate Angle:
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We need to find an integer n such that θ = 45° + 180° * n and θ > 7470°.
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Let's solve for n : 45 + 180*n* > 7470
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180*n* > 7425
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n > 41.25
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The smallest integer n that satisfies this condition is n = 42.
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Therefore, θ = 45° + 180° * 42 = 45° + 7560° = 7605°.
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Calculate 60 * θ
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60 * θ = 60 * 7605° = 456300°
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Here's the solution:
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Solve cos(θ) = sin(θ): This is true when θ = 45° + 180° * n.
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θ > 83 * 90 = 7470°
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Find n such that θ = 45 + 180*n > 7470. The smallest integer is n=42.
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Therefore, θ = 45° + 180° * 42 = 7605°.
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60 * θ = 60 * 7605° = 456300°.
So, 60 * θ = 456300°