Physics Thermodynamics

Derive van der Waals equation of state of gas?

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Derive van der Waals equation of state of gas?

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Deriving the van der Waals equation of state involves modifying the ideal gas law to account for the finite size of gas molecules and the attractive forces between them. Here’s a step-by-step derivation:

  1. Ideal Gas Law

    The ideal gas law is given by:

    PV = nRT

    Where:

    • P is the pressure,
    • V is the volume,
    • n is the number of moles,
    • R is the ideal gas constant,
    • T is the temperature.
  2. Correction for Molecular Volume

    In an ideal gas, molecules are considered point masses. However, real gas molecules occupy a finite volume, reducing the space in which they can move. The effective volume is reduced by nb, where b is the volume excluded per mole of gas. Therefore, the corrected volume V' is:

    V' = V - nb
  3. Correction for Intermolecular Forces

    Ideal gas molecules do not interact. In reality, gas molecules attract each other, reducing the pressure exerted on the container walls. This reduction in pressure is proportional to the square of the concentration (n/V). The corrected pressure P' is:

    P' = P + a(n/V)^2

    Where a is a constant that depends on the strength of the attractive forces between the molecules.

  4. Van der Waals Equation

    Substitute the corrected pressure P' and corrected volume V' into the ideal gas law:

    P'V' = nRT

    Which gives:

    (P + a(n/V)^2)(V - nb) = nRT

    This is the van der Waals equation of state.

In summary, the van der Waals equation accounts for the volume occupied by gas molecules and the attractive forces between them, providing a more accurate description of real gases compared to the ideal gas law.

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Wrote answer · 3/14/2025
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