Mathematics Algebra

How to solve 1/(X+Y) + 2x/(x^2+y^2) + 4x^3y^4/(y^8-x^8)?

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How to solve 1/(X+Y) + 2x/(x^2+y^2) + 4x^3y^4/(y^8-x^8)?

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To solve the expression 1/(X+Y) + 2X/(X^2+Y^2) + 4X^3Y^4/(Y^8-X^8), we can simplify it step by step.

  1. Rewrite the expression:
  2. The given expression is:

    1/(X+Y) + 2X/(X^2+Y^2) + 4X^3Y^4/(Y^8-X^8)

  3. Factor the denominator of the third term:
  4. Notice that (Y^8 - X^8) can be factored as a difference of squares:

    Y^8 - X^8 = (Y^4 + X^4)(Y^4 - X^4) = (Y^4 + X^4)(Y^2 + X^2)(Y^2 - X^2) = (Y^4 + X^4)(Y^2 + X^2)(Y + X)(Y - X)

  5. Rewrite the expression using the factored form:
  6. 1/(X+Y) + 2X/(X^2+Y^2) + 4X^3Y^4/((Y^4+X^4)(Y^2+X^2)(Y+X)(Y-X))

  7. Combine the first two terms:
  8. Find a common denominator for the first two terms, which is (X+Y)(X^2+Y^2):

    [1/(X+Y)] + [2X/(X^2+Y^2)] = [(X^2+Y^2) + 2X(X+Y)] / [(X+Y)(X^2+Y^2)]

    = (X^2 + Y^2 + 2X^2 + 2XY) / ((X+Y)(X^2+Y^2))

    = (3X^2 + 2XY + Y^2) / ((X+Y)(X^2+Y^2))

  9. Look for a pattern or further simplification:
  10. Now we have:

    (3X^2 + 2XY + Y^2) / ((X+Y)(X^2+Y^2)) + 4X^3Y^4/((Y^4+X^4)(Y^2+X^2)(Y+X)(Y-X))

    This expression is quite complex and does not appear to simplify easily into a compact form.

  11. Alternative approach
  12. Consider combining the first and second terms like so:

    1/(X+Y) + 2X/(X^2+Y^2) = (X^2+Y^2+2X(X+Y))/((X+Y)(X^2+Y^2))

    = (X^2+Y^2+2X^2+2XY)/((X+Y)(X^2+Y^2))

    = (3X^2+2XY+Y^2)/((X+Y)(X^2+Y^2))

    Which doesn't lead to a clear simplification when combined with the third term.

Given the complexity, it's likely that the problem is designed to be simplified using a specific substitution or context that isn't provided. If there's no further context, the expression remains as is or might require numerical methods for specific X and Y values.

Wrote answer · 3/14/2025
Karma · 40

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